assign 1 instead of the result of htole16(1) to a uint8_t.

assign 1 instead of the result of htole16(1) to a uint8_t.

on big endian archs the 1 is shifted to the high byte, which then
gets lost when it's assigned to the uint8_t. at worst we lose the
value, at best the compiler has a teary and fixes it.

this is the fix for a compiler teary.

ok claudio@